Find the Quadratic function Y=Ax^2+C with the graph that has the given point (0,-3) and (1,-7)

Question

^{The quadratic function I was told to find is missing the Bx term, making it just Y=Ax^2+C.}

Answer 1

y(x)=ax^2+c

y(0) = c = -3

y(1) = a - 3 = -7 --> a = -4

y = -4x^2 -3

Answer 2

(0,-3) --> C = -3

Y = Ax^2 - 3

(1,-7) ---> -7 = A(1)^2 - 3

= A - 3

A=-4

y = -4x^2-3