
Patrick B. answered 10/14/20
Math and computer tutor/teacher
x=-1 is a solution so x+1 is a factor
since 2-5i is a solution, ASSUMING the polynomial
has REAL coefficients, then 2 + 5i is also a solution...
The polynomial is f(x) = (x+1) [ (x-2)+ 5i ][ (x-2) - 5i ]
= (x+1) [ (x-2)^2 + 25 ]
= (x+1) [ x^2 - 4x + 4 + 25]
= (x+1) (x^2 -4x + 29)
x^3 + x^2
- 4x^2 - 4x
+ 29x + 29
x^3 - 3x^2 + 25x + 29