Hello, Ryry,
I don't see a question written, so I'll assume it relates to making an equation that models this loan as a function of time. I set time as X and loan amount as Y. IPut that into standard format of:
Y = mX + b
and look at the data to see what the slope (m) is. I can see that for the three data points, the loan is dropping by $100 every month, or $100/month. That is the slope. The y-intercept is the value at X = 0, which is $1200.
So the equation for these three points is Y = -100X + 900.
If X = 2 months, Y would be $1000, and so on.
Hopefully this answers what you are trying to find. For me, $1,200 seems like a lot for a computer, so the other answer might be "Wait! What are you getting for all that money? Did you comparison shop at all? Don't be a fool. I've got one I'll sell ya for $1100."
Bob
