Ibrahim D. answered 10/13/20
Stuart P.
asked 10/13/20Find the solution to the system x+y=10 x^2+y^2=25
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Patrick B. answered 10/13/20
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y = 10-x
x^2 + (10-x)^2 = 25
x^2 + 100 - 20x + x^2 = 25
2x^2 - 20x + 75 = 0
x = [20 +or- sqrt( 400 - 4 *2*75)] / 4
x = [20 +or- sqrt(-200))/4
= [ 20 +or- 10*i*sqrt(2)]/4
= [ 10 +or- 5 i* sqrt(2)]/2
= 5 +or- (5/2) i sqrt(2)
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