heres a cs question

Question

Consider the following code segment, which is intended to find the average of two positive integers, x and y.

int x;

int y;

int sum = x + y;

double average = (double) (sum / 2);

Which of the following best describes the error, if any, in the code segment?

a) There is no error, and the code works as intended.

b) In the expression (double) (sum / 2), the cast to double is applied too late, so the average will be less than the expected result for even values of sum

c) In the expression (double) (sum / 2), the cast to double is applied too late, so the average will be greater than the expected result for even values of sum

d) In the expression (double) (sum / 2), the cast to double is applied too late, so the average will be less than the expected result for odd values of sum.

e) In the expression (double) (sum / 2), the cast to double is applied too late, so the average will be greater than the expected result for odd values of sum.

Answer 1

The cast is applied to late, the result will be less than expected for odd sums...

The other part of problem is that the division operator for integers returns only an integer...

To force the coercion, the divisor should be a float...

see the code below

using namespace std;

#include <iostream>

int main()

{

int x=4;

int y=5;

int sum = x + y;

double average = (double) (sum / 2.0f);

cout <<average << endl;

}