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Question

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 80%

 pure antifreeze. The company wants to obtain 320

 gallons of a mixture that contains 40%

 pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed? 

Answer 1

Let x = number of gallons of water (which is 0% antifreeze) to be added

Then, 320 - x = number of gallons of the 80% antifreeze solution

So, 0.8(320 - x) + 0x = = 0.40(320)

256 - 0.80x = 128

-0.80x = -128

x = 160 gal

Use 160 gal of each to get the desired solution.