find 3 consecutive integers such that the sum of twice the smallest number and three times the largest is 42

Answer 1

x, x+1 and x+2

2x + 3(x+2) = 42

5x + 5 = 42

5x = 37

x = 37/5 which is not an integer, 7 2/5, 8 2/5 and 9 2/5 is as close as it gets

7, 8 and 9 are the closest integers

2x7 + 3x9 = 14 +27 = 41, which is close to 42