
Jon S. answered 10/08/20
Patient and Knowledgeable Math and English Tutor
c(x) = 6700
6700 = x^2 - 60x + 2700
x^2 - 60x + 2700 = 6700
x^2 - 60x - 4000 = 0
(x-100)(x+40) = 0
x = 100 or x = -40 (not valid)
number of units = 100
Dee M.
asked 10/08/20The cost to manufacture x units of a certain product is given by C(x)=x2-60x+2700. Find the number of units that can be manufactured for a cost of $6700
Jon S. answered 10/08/20
Patient and Knowledgeable Math and English Tutor
c(x) = 6700
6700 = x^2 - 60x + 2700
x^2 - 60x + 2700 = 6700
x^2 - 60x - 4000 = 0
(x-100)(x+40) = 0
x = 100 or x = -40 (not valid)
number of units = 100
The cost to manufacture x units of a certain product is given by C(x)=x2-60x+2700. Find the number of units that can be manufactured for a cost of $6700
Given total cost = 6700
x = Number of units
So 6700 = X2 -60X +2700
subtracting 6700 from both sides
6700 -6700 = X2 -60X +2700 -6700
0 = X2 - 60X - 4000
We need to solve this equation for X
Rewriting this equation
X2 - 60X -4000 = 0
Solving for X
X = 30 + √1300 and X = 30 - √1300
So x values are 30 + 36.05 or -36.05
So the Answer is 66 units
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Dr Gulshan S.
10/08/20