(1/3)(6x - 5) - x = 1/3 - 2(x + 1)
2x - 5/3 - x = 1/3 - 2x - 2
2x - x + 2x = 5/3 + 1/3 - 2
3x = 0
x = 0
0 + 1 = 1
Daniel F.
asked 10/07/20Find the value of (x + 1) in this equation.
(1/3)(6x - 5) - x = 1/3 - 2(x + 1)
2x - 5/3 - x = 1/3 - 2x - 2
2x - x + 2x = 5/3 + 1/3 - 2
3x = 0
x = 0
0 + 1 = 1
Yefim S. answered 10/07/20
Math Tutor with Experience
2x - 5/3 - x = 1/3 - 2x - 2; 3x = 0, x = 0/3; x = 0, x + 1 = 1
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