Raymond B. answered 10/06/20
Tutor
5
(2)
Math, microeconomics or criminal justice
4(b-6) = b^2
4b-24 = b^2
b^2 -4b + 24 = 0
b^2 -4b + 4 + 24 = 4
(b-2)^2 = 4-24 = -20
b-2 = + or - sqr(-20)
b = 2 + or - 2isqr5
b = 2 + 2isqr5 or 2-2isqr5
= about 2+ 4.4i or 2- 4.4i
there is no real solution, just 2 complex solutions