Find four consecutive odd integers such that the sum of the first three is 30 more than the fourth

Answer 1

x = first odd integer

x+2 = second odd integer

x+4 = third odd integer

x+6 = fourth odd integer

sum of first three = x + x + 2 + x + 4 = 3x + 6

30 more than 4th = x + 6 + 30 = x + 36

sum of first three = 30 more than 4th

3x + 6 = x + 36

2x = 30

x = 15

integers are 15, 17, 19, 21

sum of 1st three = 51

which is 30 more than 4th (21)