Mark M. answered 10/05/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Here is a non-algebraic approach:
Recall that f'(c) = limx→c[(f(x) - f(c)) / (x - c)]
Let f(x) = √(x+4). Then f(0) = 2
So, the given limit can be expressed as limx→0 [(f(x) - f(0)) / (x - 0)] = f'(0)
Since f'(x) = 1 / [2√(x + 4)], we have f'(0) = 1/4.