
Jon S. answered 10/01/20
Patient and Knowledgeable Math and English Tutor
y = 2x + 4
y = 2x - 2
express in form ax + by + c = 0
2x - y - 4 = 0
2x - y + 2 = 0
A = 2, B = 1, C2 = 2, C1 = -4
d = abs ((C2 - C1)/sqrt(A^2 + B^2)) = 6/sqrt(5) = 2.68
Damon L.
asked 10/01/20Find the distance between the pair of parallel lines; y = 2x + 4 and y = 2x – 2.
a. 2.68
b. 2.75
c. 2.94
d. 3.11
Jon S. answered 10/01/20
Patient and Knowledgeable Math and English Tutor
y = 2x + 4
y = 2x - 2
express in form ax + by + c = 0
2x - y - 4 = 0
2x - y + 2 = 0
A = 2, B = 1, C2 = 2, C1 = -4
d = abs ((C2 - C1)/sqrt(A^2 + B^2)) = 6/sqrt(5) = 2.68
Mark M. answered 10/01/20
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram!
Distance is measured on the normal (perpendicular) to the lines.
The normal to the first equation passing through the same y-intercept is
y = -0.5x + 4
This normal intersects the second line when
-0.5x + 4 = 2x - 2
6 = 2.5x2.8
2.4 = x, or at (2.4, 2.8))
The normal is from (0, 4) to (2.4, 2.8)
Use the distance formula to determine the distance tween the two points
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Tom K.
or just calculate 6/sqrt(1^2+2^2)10/01/20