Michael M. answered 10/01/20
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Assume that f(1)=2 is the first term of the sequence (since it is not explicitly stated), and that the whole numbers are *CONSECUTIVE* whole numbers beginning with 1. Then if f(n)=2*f(n-1)+4 for each whole number n greater than 1, then the remaining three consecutive whole numbers n greater than 1 are 2,3 and 4.
The formula given is recursive, so each solution may be used in calculating the next term:
n=1: f(n)=f(1)=2 (given)
n=2: f(n)=2*f(n-1)+4, or f(2)=2*f(2-1)+4=2*f(1)+4=2*2+4=8
n=3: f(n)=2*f(n-1)+4, or f(3)=2*f(3-1)+4=2*f(2)+4=2*8+4=20
n=4: f(n)=2*f(n-1)+4, or f(4)=2*f(4-1)+4=2*f(3)+4=2*20+4=44
Then the first four terms of the sequence are: 2,8,20,44.