Unit 2 mid unit assessment

Question

Find find three consecutive odd integers such that when three times the first is added to twice the third there is all to 17 less than 6 times the second

Answer 1

n

n + 2

n + 4

3n + 2(n + 4) = 6(n + 2) - 17

3n + 2n + 8 = 6n + 12 - 17

-n = -13

n = 13

13, 15, 17