How do i solve in terms of x?

Question

g(x) = 3x-4

h(x)= 2/ (2x+3)

How do i write this in terms of x?

Answer 1

inorder to solve in terms of x, you must set both equations equal to each other:

3x-4= 2/(2x+3)

here we can multiply each side by (2x+3) to simplify to get:

(3x-4)(2x+3)=2

Then foil it to get a polynomial:

6x²+9x-8x-12=2

Simplify:

6x²+x-12=2 >> 6x²+x-14=0

then use the quadratic formula to solve:

(-b+sqrt(b^2-4ac))/2a or (-b-sqrt(b^2-4ac))/2a

= (-1+sqrt(1-4(*6*-14)))/2(6) or (-1-sqrt(1-4(*6*-14)))/2(6)

and there are two answers: x= -1.613 or 1.446