Given zero: x = 2i → x - 2i = 0
This has a conjugate pair.
x = -2i → x + 2i = 0
(x + 2i)(x - 2i) = x2 - 2xi + 2xi - 4i2 = x2 - 4(-1) = x2 + 4
Do long division:
(x3 + x2 + 4x + 4) ÷ (x2 + 4) = x + 1
Here are the zeros: x = -1, 2i, -2i
Alex S.
asked 09/25/20Use the given zero to find all the zeros of the function. (Enter your answers as a comma-separated list. Include the given zero in your answer.)
Function: f(x) = x^3 + x^2 + 4x + 4
Zero: 2i
Given zero: x = 2i → x - 2i = 0
This has a conjugate pair.
x = -2i → x + 2i = 0
(x + 2i)(x - 2i) = x2 - 2xi + 2xi - 4i2 = x2 - 4(-1) = x2 + 4
Do long division:
(x3 + x2 + 4x + 4) ÷ (x2 + 4) = x + 1
Here are the zeros: x = -1, 2i, -2i
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