
Kasie S. answered 09/25/20
Every student deserves the opportunity to be successful
To find an inverse function always start by switching all your variables.
f(x) = 3x+(6/x)+2
rewrite with x and y:
y = 3x+(6/x)+2
no replace every y with an x and every x with a y:
x=3y+(6/y)+2
Now solve for y (note this is a challenging one because we have y in the numerator and denominator postions!)
xy=3y2+6+2y
0=3y2+(x+2)y+6 <-- not very pretty but what you have here is a quadratic!
a=3
b=(x+2)
c=6
y=(-b+sqrt(b2-4ac))/(2a), (-b-sqrt(b2-4ac))/(2a)
plug in for a, b, and c
f-1(x)= (-x-2+sqrt( (x+2)2-4(3)(6) )) / (2*3)
= (-x-2+sqrt( x2+4x+4-72 )) / 6
= (-x-2+sqrt(x2+4x-68))/6
I'll let you work the algebra out on the second equation for the other half of the inverse. Good luck!