
Randall S. answered 09/25/20
Experienced HS/college math tutor
follow the recipe to find the inverse.
- change f(x) to y and rewrite. y = (x−3)2
- switch the x and y x = (y−3)2
- solve for y √x = √(y−3)2
√x = y - 3
√x + 3 = y or y = 3 + √x
now rewrite the y as f-1(x)
f-1(x) = 3 + √x
the domain of this inverse is only defined when you can take the square root of x and get a real number, so the domain of f-1(x) = 3 + √x is when x ≥ 0.
also, since you are adding a growing real number (the square root of x) to 3, as x gets bigger, the inverse is always increasing, so the inverse is non-decreasing over its entire domain.