Sagan S.

asked • 09/24/20

Question 26 This question is a long free-response question. Show your work for each part of the question.

The figure presents a diagram labeled, Motion of a Sphere. In the diagram, the sphere is launched horizontally to the right above the floor, with an initial velocity of v sub 0. The direction horizontally to the right is labeled, plus x and the direction downward is labeled, plus y. The sphere follows a path that curves downward and to the right until reaching the floor


Students are studying the two-dimensional motion of objects as they move through the air. Specifically, they are examining the behavior of a sphere that is launched horizontally from a location above the floor with an initial velocity v0 in the +x direction, as shown in the figure. The students assume that the positive directions are along the sphere’s initial velocity for horizontal motion and downward for vertical motion.


The horizontal displacement of the object from its starting point is x , and the vertical displacement of the object from its starting point is y . One of the students derives an equation for y in terms of x and other quantities. After examining the equation, the student claims that y is proportional to x2 .


(a) Derive an equation for the vertical coordinate y of the sphere as a function of x , v0 , and physical constants, as appropriate.

1 Expert Answer

By:

Anthony T. answered • 09/24/20

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Annie L.

how'd you get the final equation? like where exactly did the first equation come from (like the .5) and then the 2 in the last one?
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09/30/20

Anthony T.

Hi, Annie I am sorry to have confused you. The 0.5 is another way of writing 1/2. In the last equation, I changed the 0.5 which would have been in the denominator back to 1/2 which then placed the 2 into the numerator. Thank you for pointing that out. I will learn to be more consistent! It does show, however, that y is proportional to x squared.
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09/30/20

Jaime C.

What is the .5 in your first step: t (time): y = 0.5 x g x t2 ? I know .5 is the same as 1/2 but where did you get the .5 from? Is g = gravity? And what is t2? Is that time squared? Was that provided in the problem?
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01/07/21

Anthony T.

Physics texts usually write this equation as y =1/2 g t^2. g is the acceleration due to gravity, and t stands for time which is squared.
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01/08/21

Jaime C.

Thank you, Anthony! I really appreciate it.
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01/08/21

Anthony T.

You are quite welcome! We really appreciate it when we get feedback.
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01/08/21

Tobias C.

Why is there no 1/2at^2 for the second step?
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09/17/22

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