
Murray B. answered 09/21/20
Experienced Algebra 1 teacher
length = L. Width = L + 37. Perimeter = 2(L) + 2(W)
so, 2L + 2(L + 37) = 348
2L + 2L + 74 = 348
4L = 274
L = 68.5 meters
Luke B.
asked 09/21/20Murray B. answered 09/21/20
Experienced Algebra 1 teacher
length = L. Width = L + 37. Perimeter = 2(L) + 2(W)
so, 2L + 2(L + 37) = 348
2L + 2L + 74 = 348
4L = 274
L = 68.5 meters
John H. answered 09/21/20
Aerospace Engineer, skilled tutor - math up to and including calc 2
The question gives you a system of equations in words:
L=W+37 (Length is 37 more than width)
P=348=2L+2W (the equation for perimeter)
Solve for W in either equation and then substitute into the other equation. I will solve for W using the first equation:
W=L-37
Now substitute into second equation:
348=2L+2(L-37)
Finally, expand and solve for L
348=2L+2L-2*37
348=4L-74
348+74=4L
422=4L
L=105.5 meters
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