First, we want to define some quantities so that we can translate this from a word problem to something we can see visually in equation form.
Let K = amount of money in $ that Kira has, A = amount of money in $ that Alonzo has, and B = amount of money in $ that Bob has.
We know that the total amount of money is $130, so we can say:
K + A + B = $130
We then are told that Bob has 3x as much money as Alonzo, so we can say:
B = 3A
Finally, we're told that Alonzo has $10 less than Kira, so we can say:
A = K – 10
The trick to questions like these is being able to find define one term in terms of the others, and then substitute these into our main equation to solve for that term, and then use it to find our other variables.
I see that I have A present in all 3 equations so far, so I am going to find B in terms of A, and K in terms of A, substitute these into my equation for total money, and solve for A.
A = K − 10, so K = A + 10
B = 3A
K + A + B = $130
By substitution,
(A + 10) + (A) + (3A) = 130
Combine like terms:
5A + 10 = 130
5A = 120
A = $24
Now, I can plug my value for A into my other equations to solve for B and K.
K = 24 + 10
K = $34
B = 3*24
B = $72
Therefore, Alonzo has $24 in his wallet, Kira has $34 in her wallet, and Bob has $72 in his wallet.
We can check our work by plugging our values for A, K, and B into our initial equation. We should find that the total values of Alonzo, Kira, and Bob's wallets equals $130.
K + A + B = $130
$34 + $24 + $72 = $130