Determine the ΔH for the formation of ONE MOLE of each of product in the following equations, include the appropriate sign. C(s) + 4 H2(g) + O2(g) ––––––––––––> 2 CH3OH(g) + 402 kJ ΔH =

Question

I need some help please, I don't understand how to do this question:

Determine the ΔH for the formation of ONE MOLE of each of product in the following equations, include the appropriate sign.

C(s) + 4 H2(g) + O2(g) ––––––––––––> 2 CH3OH(g) + 402 kJ

ΔH = ?

Answer 1

The ∆H for production of TWO moles CH3OH in the reaction shown is +402 kJ.

So, the ∆H for production of ONE mole CH3OH would be 1/2 of 402 kJ = +201 kJ