
Christopher J. answered 09/18/20
Berkeley Grad Math Tutor (algebra to calculus)
Simplify the expression
7x-x+7 = 3x(x-4+20)
6x+7 =3x(x+16)
6x+7=3x2+48x
3x2+42x-7 = 0
check discriminant b2-4ac = (42)2-4*3*(-7) to see how many solutions exist.
Da'Nasia W.
asked 09/18/20Christopher J. answered 09/18/20
Berkeley Grad Math Tutor (algebra to calculus)
Simplify the expression
7x-x+7 = 3x(x-4+20)
6x+7 =3x(x+16)
6x+7=3x2+48x
3x2+42x-7 = 0
check discriminant b2-4ac = (42)2-4*3*(-7) to see how many solutions exist.
Question: does 7x-x+7=3x(x-4+20) have a solution
Simplify the expression.
6x + 7 = 3x^2 -12x + 60x
Since there is an x-squared, the equation is a quadratic. Move all terms to one side and set the equation equal to 0. Combine the like terms.
-3x^2 + 6x + 12x - 60x + 7 = 0
-3x^2 - 42x + 7 = 0
3x^2 + 42x -7 = 0
Use the coefficients for each term to check for the solution(s).
a = 3, b = 42, and c = -7
Since you only want to know if there is a solution, use the discrimanant. It is the expression under the square root in the quadratic formula.
b^2 - 4•a•c
42^2 - 4 • 3 • (-7)
Answer: Yes
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