Calculate the number of moles of Cl- ions in 1.75 L of 1.00 x 10-3 M ZnCl2 solution

Question

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Answer 1

ZnCl₂ ==> Zn²⁺ + 2Cl^-

For each 1 mole of ZnCl₂ you will get 2 moles of Cl^- ions

So all we have to do now is find out how many moles of ZnCl₂ we have and double it to find moles of Cl^- ions

1.75 L x 1.00x10^-3 mol/L = 1.75x10^-3 moles of ZnCl₂

1.75x10^-3 mol ZnCl₂ x 2 mol Cl^-/mol ZnCl² = 3.50x10^-3 moles of Cl^- ions