Calculate the concentration of a solution made by dissolving 45.6 grams of Fe2(SO4)3 to 475 mL What is the concentration of each ion?

Question

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Answer 1

molar mass of Fe₂(SO₄)₃ = 399.88 g/mol

475 ml = 0.475 L

Molarity = moles solute/liter solution

moles solute = 45.6 g x 1 mol/399.88 g = 0.114 moles Fe₂(SO₄)₃

Molarity (M) = 0.114 moles/0.475 L = 0.240 M Fe₂(SO₄)₃ THIS IS THE CONCENTRATION OF THE SOLN.

To find concentration of each ion, we look at the dissociation of Fe₂(SO₄)₃

Fe₂(SO₄)₃ ==> 2Fe³⁺ + 3SO₄^2-

[Fe³⁺] = 2 x 0.240 M = 0.480 M

[SO₄^2-] = 3 x 0.240 M = 0.720 M