For continuous growth use the formula
y=A(e^kt) where A is initial amount
k is growth rate and t=time
y= 3700(e^ (0.05)(6)
y= 3700(e^.3)= 4944
Alexandria B.
asked 09/18/20Jocelyn invested $3,700 in an account paying an interest rate of 1.5% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 6 years?
For continuous growth use the formula
y=A(e^kt) where A is initial amount
k is growth rate and t=time
y= 3700(e^ (0.05)(6)
y= 3700(e^.3)= 4944
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