Rodger N. answered • 09/18/20

Your success is my goal

This is a dilution problem hiding out as density. Remember the formula for dilution:

M_{1}V_{1} = M_{2}V_{2}

Where M is Molarity (concentration) and V is volume. Molarity is how many moles of a substance can be found in a given volume.Density is how much mass is found in a given volume, ie concentration. So Density can be substituted for Molarity in the equation giving:

D_{1}V_{1} = D_{2}V_{2} I'm going to use the pure as D_{1} and V_{1}

(1.84g/ml)V_{1} = (1.27g/ml)(5.0L)

Solving for V_{1} gives 3.5L in correct significant figures. The question could ask for how much water would be used for dilution and in this case would be 1.5L.