Rodger N. answered 09/18/20
Your success is my goal
This is a dilution problem hiding out as density. Remember the formula for dilution:
M1V1 = M2V2
Where M is Molarity (concentration) and V is volume. Molarity is how many moles of a substance can be found in a given volume.Density is how much mass is found in a given volume, ie concentration. So Density can be substituted for Molarity in the equation giving:
D1V1 = D2V2 I'm going to use the pure as D1 and V1
(1.84g/ml)V1 = (1.27g/ml)(5.0L)
Solving for V1 gives 3.5L in correct significant figures. The question could ask for how much water would be used for dilution and in this case would be 1.5L.