Irene R. answered 09/15/20
BS in Mechanical Engineering and Certified math teacher for 13 years
Hi Domenic,
Let's use the variable, c, represent the cost of 1 chair and the variable, t, represent the cost of 1 table.
We can write the following equations to represent the situation described in your problem:
2c + 6t = 42
5c + 3t = 30
Now we can solve these two equations with two unknowns to find the cost of each chair or table.
Multiply the second equation by -2 to find the cost of 1 chair:
5c + 3t = 30 becomes -10c - 6t = -60
Now combine this "new" equation with the original first one:
2c + 6t = 42
-10c - 6t= -60
-8c = -18
c = 18/8 or $2.25
The cost to rent 1 chair was $2.25
Now substitute this value for c into either original equation to find the cost to rent 1 table:
2c + 6t = 42
2 • 2.25 + 6t = 42
4.50 + 6t = 42
4.50 + 6t - 4.50 = 42 - 4.50
6t = 37.50
t= %6.25
The cost to rent 1 table was $6.25

Irene R.
09/16/20
Domenic J.
Thanks so much for your help Irene I truly appreciate it.09/16/20