One number is four less than the second number.Three times the first is 9 more than 6 times the second.find the numbers

Answer 1

Let the first number be x and the second number be y.

One number is four less than the second number: y-4

Three times the first number is 9 more than 6 times the second: 3(y-4)=6y+9

Now you can solve for y, then x.

Answer 2

One number is four less than a second:

n - 4, and n

Three times the first:

3(n - 4)

Is

=

9 more

+9

Than 6 times the second

6n

3(n - 4) = 6n + 9