Write the slope-intercept form of through (1,-3) and parellel to y=x+3

Answer 1

Another way to solve is to solve for b, then plug it in.

y = mx + b

-3 = 1(1) + b

b = -4

y = x - 4

Answer 2

Hey Michael, in order to find a line parallel to y=x+3 and going through the point, we need to use the point slope formula. To start, we know the slope is 1, since the line is parallel to y=x+3.

y-y1=m(x-x1)

y-(-3)=1(x-1)

y+3=x-1

y=x-4

Let me know if you have any questions.

Thanks!