Raymond B. answered 09/11/20
Math, microeconomics or criminal justice
Let A,B, and C be the 3 angles
B=2A-5
C=3A-13
A+B+C=180
A+2A-5+3A-13=180
6A=180+13+5=198
A=198/6=33 degrees
B=2A-5=66-5=61 degrees
C=3A-13=99-13=86 degrees
Shhshns D.
asked 09/11/20The Second angle of a triangle is five less than twice that of the first angle and the third angles is 13 less than three times the first angle. Find each angle.
Raymond B. answered 09/11/20
Math, microeconomics or criminal justice
Let A,B, and C be the 3 angles
B=2A-5
C=3A-13
A+B+C=180
A+2A-5+3A-13=180
6A=180+13+5=198
A=198/6=33 degrees
B=2A-5=66-5=61 degrees
C=3A-13=99-13=86 degrees
Jon S. answered 09/11/20
Patient and Knowledgeable Math and English Tutor
x = measure of first angle
2x -5 = measure of second angle
3x - 13 = measure of third angle
sum of measures of a triangle is 180 degrees so
x + (2x-5) + (3x-13) = 180
6x - 18 = 180
x = 33 (first angle)
2x - 5 = 2(33)-5 = 61 (second angle)
3x - 13 = 3(33) - 13 = 86 (third angle)
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