Let f(x) = 3x^2 + x-4 and g(x) = √x+7, what is (f+g)(2)?

Answer 1

For this one, I'd recommend finding f(2) and g(2) and simply adding together the two values. Both of these are pretty straightforward:

f(2)=3(2)²+2-4=10

For g(x), I am not sure whether or not the 7 is included under the radical, so I will solve it both ways, marking them g₁(x) and g₂(x). The first will be the case where the 7 is not under the square-root symbol.

g₁(2)=√2+7

g₂(2)=√(2+7)=√9=3

So the answer to (f+g)(2) is either 10+√2+7=17+√2 or 13, depending on the notation given for g(x).

I hope this helped!

Answer 2

f(x) = 3x^2 + x-4 and g(x) = √x+7, what is (f+g)(2)?

if

f(x) = 3x^2 + x-4

g(x) = √(x+7)

Then

(f+g)(x) = f(x) + g(x) = 3x^2 + x-4 + √(x+7).

Therefore,

(f+g)(2) = 3(2)^2 + 2-4 + √(2+7)

= 3*9+2-4+√(9)

= 3*9+2-4+3.

= 27+2-4+3.

= 28.