(f-g)(x) = f(x) - g(x) = 3x^2 - x - 5 - (x^2 - 8) = 2x^2 - x + 3
(f*g)(x) = f(x) * g(x) = (3x^2 -x -5) * (x^2 - 8) = 4x^4 - x^3 - 5x^2 - 24x^2 + 8x + 40 = 4x^4 - x^3 - 29x^2 + 8x + 40
Peter P.
asked 09/07/20a. What is (f-g)(x)?
b. Evaluate (f*g)(2)
(f-g)(x) = f(x) - g(x) = 3x^2 - x - 5 - (x^2 - 8) = 2x^2 - x + 3
(f*g)(x) = f(x) * g(x) = (3x^2 -x -5) * (x^2 - 8) = 4x^4 - x^3 - 5x^2 - 24x^2 + 8x + 40 = 4x^4 - x^3 - 29x^2 + 8x + 40
Jonathan S. answered 09/08/20
Experienced Math Educator and Former Google Software Engineer
If f(x) = 3x^2 - x-5 and g(x) = x^2 - 8
Then
(f-g)(x) = f(x) - g(x) = 3x^2 - x-5 -(x^2 - 8) = 3x^2 - x-5 -x^2 + 8= 3x^2-x^2 - x + 8 -5
= 2x^2 - x + 3
and
(f*g)(x) = (3x^2 - x-5)(x^2 - 8).
Therefore
(f*g)(2) = (3(2)^2 - 2-5)(2^2 - 8)
= (12 - 2 - 5)(4 - 8) = 5*(-4)
=-20
Michael M. answered 09/08/20
Skilled math and science tutor with 10+ years of experience
First we start with the definition of our functions:
The notation is defined to mean
. Substituting the definitions of
and
:
Distributing the negative sign through the right set of parentheses:
Collecting like terms:
Simplifying:
The notation is defined to mean
. Substituting the definitions of
and
:
Distributing \left(3x^2-x-5\right) through \left(x^2-8\right):
Expanding:
Collecting like terms:
Simplifying:
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