Let the integers be. x and x+1
Then x + (x+1) = 101
2x = 100
x = 50
The integers are 50 and 51.
Let the integers be. x and x+1
Then x + (x+1) = 101
2x = 100
x = 50
The integers are 50 and 51.
Jorge H. answered 09/07/20
Experienced Tutor: 3rd Year Undergraduate at UC Irvine
For this sort of question, we want to start off by asking what two consecutive numbers looks like algebraically. Some examples of consecutive numbers are 1 and 2, 6 and 7, 100 and 101, and so on. Noticing the pattern, it is simply a number and that same number plus 1. We can write this as:
n and (n+1)
We're asked to find what these two would be if their sum were 101. So we can make an equation for this:
n + (n+1) = 101
Simplifying this equation by combining the like terms, we get:
2n+1=101, subtract by 1 on both sides:
2n=100, divide by 2 on both sides:
n=50
Then our two consecutive numbers that sum to 101 are 50 and 50+1 or 50 and 51. You can add these together and see that they do indeed add up to 101.
Great question, Peg!
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