Arthur D. answered 09/07/20
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
J=Josh's time
J-9=Danny's time
Josh paints 1/J of the fence in one hour
Danny paints 1/(J-9) of the fence in one hour
they take 7 hours together to paint the fence
7(1/J)+7(1/[J-9])=1 (job finished)
LCD=J(J-9)
multiply both sides by the LCD to get...
7(J-9)+7(J)=J(J-9)
7J-63+7J=J^2-9J
J^2-9J-14J+63=0
J^2-23J+63=0
using the quadratic formula....
[23±√(529-252)]/2
[23±√277]/2
(23±16.64)/2
(23+16.64)/2 (using -16.64 gives a negative time for Danny)
39.64/2
19.82 hours is Josh's time alone
10.82 hours is Danny's time alone
the difference is 9 hours
also 7/19.82 + 7/10.82=0.3531+0.6469=1 (job finished)