find three consecutive even integers such that six less than three times the first is equal to the sum of the second and third

Answer 1

Three consecutive even integers are:

First x

Second x+2

Third x+4

six less than three times the first 3x-6 is equal to the sum of the second and third x+2+x+4

3x-6=x+2+x+4

Combine like terms

3x-6=2x+6

Subtract 2x from both sides

x-6=6

Add 6 to both sides

x=12

The three would be

x=12

X+2=14

x+4=16