To find all values of t for which g(t) = 7, set the given equation for g(t) equal to 7
g(t) = t2 - 5
7 = t2 - 5
t2 - 12 = 0
(t + √12)(t - √12) = 0
t = - √12 t = √12
So, there are 2 possible values of t for which g(t) = 7, { -√12, +√12}
To find all values of t for which g(t) = 7, set the given equation for g(t) equal to 7
g(t) = t2 - 5
7 = t2 - 5
t2 - 12 = 0
(t + √12)(t - √12) = 0
t = - √12 t = √12
So, there are 2 possible values of t for which g(t) = 7, { -√12, +√12}
Inactive Tutor answered 09/05/20
g(t) = t^2 - 5. when g(t) = 7. therefore:-
t^2 -5 = 7 add 5 to both sides
t^2 -5 + 5 = 7 + 5
t^2 = 12 square root both sides to get rid of the square (^2)
t = 2√3,−2√3 or 3.4641, -3.4641
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