Stratton K.
asked • 09/03/20Trigonometric function problem
a=11, b=6, c=23
Q: Find the value of sin A
The graphic for the question is a right triangle, with A at the top, B on the right vertex, and C is to the left of B (C is the 90 degree angle).
How would I solve this? I tried using the law of cosines but I kept getting no solution.
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2 Answers By Expert Tutors
Robert Z. answered • 09/06/20
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3965+ hours (& counting!) tutoring math -- Prealgebra to Calculus 2
Hi Stratton,
I wonder if there is a typo in what you submitted. Because (a+b)<c, these given lengths violate the triangle inequality which requires that (a+b) > c. In other words, the given lengths cannot form a triangle.
Patrick B. answered • 09/03/20
Tutor
4.7
(31)
Math and computer tutor/teacher
THen the hypotenuse is sqrt(157) by pythagorean theorem
sine A = 11/ sqrt(157) = 11*sqrt(157) / 157
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William W.
The value of c (c = 23) that you gave, doesn't make sense. You can't have a triangle where one side is 11, another side is 6 and the last side is 23. The last side must be less than 17 for this to be a triangle (let alone a right triangle).09/05/20