Patrick B. answered 08/23/20
Math and computer tutor/teacher
1) 100% - 13% = 87% = 0.87
2) 28000 * (0.87)^t = f(t)
3) f(6) = 12,141.53
4) 28000/(0.87)^(-t) = f(t)
Kaleb J.
asked 08/23/20A car depreciates at a rate of 13% per year. The car was originally purchased for $28,000.
1. What is the decay factor for the value of the car? (7 points)
2. Write a function for this situation with the value of the car as a function of the age of the car in years. (8 points)
3. How much will the car be worth in 6 years? (7 points)
4. Rewrite the function for question 2 so it is an equivalent function with a negative exponent. (8 points)
Patrick B. answered 08/23/20
Math and computer tutor/teacher
1) 100% - 13% = 87% = 0.87
2) 28000 * (0.87)^t = f(t)
3) f(6) = 12,141.53
4) 28000/(0.87)^(-t) = f(t)
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Mark M.
This appears to be a scored assignment/quiz/test. Academic honesty precludes a tutor's assistance.08/23/20