write the equation of the line that passes through (10,-3) and has a slope of 2.

Answer 1

Hi Rasheed,

Since we are dealing with Straight lines, we need to find two constants to frame the equation.

Firstly, let us analyze the question. You have slope of the line and a point on the line.

m=2; (x₁,y₁)=(10,-3)

Let us recall the formula of slope here: m = (y₂ - y₁)/(x₂-x₁)

Let us use (x₂,y₂)=(x,y) and (x_1,y₁)=(10,-3) and take m=2.

Substituting these values in the formula for slope, we get:

2=(y-(-3))/(x-10)

2=(y+3)/(x-10)

2(x-10)=y+3

y=2x-23

Answer 2

Write the equation of the line that passes through ( 10 , –3) and has a slope of 2

Step 1: Find B

Y = mx + b

– 3 = ( 2 ) ( 10 ) + b

– 3 = 20 + b

– 23 = b

Step 2: Write the equation

y = 2x –23