Stratton K.
asked 08/18/20Rational expression questions
Premise: the first two questions were to simplify ((1/x+3)+(6/x^2+4x+3))*(x+3)/(x+1), and then explain how I got there (which I did). I got the answer of (x+7)/(x+1)^2. The questions I am not sure how to answer are the following:
• Are there any values "x" cannot be? Explain.
• Find the values of "x" that make the expression equal to 0. Explain the steps you would use to find these values.
Any help is appreciated!
1 Expert Answer
Steven H. answered 08/18/20
Former teacher with 10yrs experience
Remember, that you cannot divide by 0. So set the denominator = 0 and solve. Those will be the values that will make the expression undefined.
Similarly, set the numerator to 0 and solve. That will give you the values which will make the expression equal to 0.
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Tracy D.
The answer to are there any values "x" cannot be is obtained when you set original denominators equal to zero and solve for x. These are the values X cannot be, so in this case: x cannot be equal to -3 or -1. I hope that makes sense (you cannot divide by zero).08/18/20