This is a pain to do.

A is ending amount

I is the initial amount

base is 2

exponent is a fraction time divided by period of doubling

A = I (2)^(t/ p)

100 = I(2)^(20/ p). 1500 = I(2)^(35\ p)

Take the log of everything

log(100) = log( I) + (20/ p) log(2) do the same for the other equation, then solve each for log( I).

Set the two equations equal to each other and solve for p. I came up with p = 3.839370372 and

I = 2.703200887

I is very close to e^(1), it might work better to use natural log or on. Good luck

Kayla K.

Thank you!08/09/20