This is a pain to do.
A is ending amount
I is the initial amount
base is 2
exponent is a fraction time divided by period of doubling
A = I (2)^(t/ p)
100 = I(2)^(20/ p). 1500 = I(2)^(35\ p)
Take the log of everything
log(100) = log( I) + (20/ p) log(2) do the same for the other equation, then solve each for log( I).
Set the two equations equal to each other and solve for p. I came up with p = 3.839370372 and
I = 2.703200887
I is very close to e^(1), it might work better to use natural log or on. Good luck
Kayla K.
Thank you!08/09/20