Solving a word problem using a system of equations of the form Y=Mx+b

Question

Two pools are being filled with water. To start, the first pool contains 1900 liters of water and the second pool contains 1440 liters of water. Water is being added to the first pool at a rate of 24.25 liters per minute. Water is being added to the second pool at a rate of 35.75 liters per minute.

after how many minutes will the two pools have the same amount of water?

how much water will be in each pool when they both have the same amount?

Answer 1

First pool. 24.35h + 1900

Second pool. 35.75h + 1440

h stands for hours

24.25h +1900 = 35.75h + 1440. Now solve

1900 - 1440 = 35.75h - 24.35h

460 = 11.4h

h = 40.35087719 hours

substitute in

24.35(40.35087729) + 1900 = 2682.54386 gal

35.75(40.35087729) + 1440 = 2682.54386 gal