Tony P. answered • 08/06/20

Experienced Math Teacher & Tutor: Algebra - Calculus (Online Too!)

__Question 1 __

When tossing a coin, the probability of getting a head is .50. The probability of getting a tail is .50.

When we are looking for the probability of getting 1 head on 5 coin tosses, we are looking for the probability of 5 occurrences:

**Head** (.50) and **Not Head **(.50) and **Not Head **(.50) and **Not Head **(.50) and **Not Head **(.50)

(These probabilities are multiplied)

So we have

**(.50)**^{1}** (.50)**^{4}

We also have to multiply the number of combinations of 1 head out of 5 coin tosses

_{5}C_{1} = **5**

So all together we have

**5•(.50)**^{1}** (.50)**^{4}** = .15625 There is a 15.625% chance of getting 1 head (and 4 tails) on 5 coin tosses.**

__Question 2__

Getting 4 heads when 4 coins are flipped

We are looking for the probability of:

**Head** (.50) and **Head** (.50) and **Head** (.50) and **Head** (.50)

So we have

**(.50)**^{4}

We also have to multiply the number of combinations of 4 heads out of 4 coin tosses

_{4}C_{4} = 1

So all together we have

**1•(.50)**^{4}** = .0625 There is a 6.25% chance of getting 4 heads out of 4 coin tosses**

__Question 3__

The odds in favor of rolling two consecutive odd numbers when a pair of dice is rolled

The probability of rolling an odd number is 3/6 or .50

So we are looking for the following probability:

Odd (.50) and Odd (.50)

So we have:

**(.50)•(.50) = .25 There is a 25% chance of rolling two consecutive odd numbers when a pair of dice is rolled.**