money word problem

Question

sugar addict #1 paid $40.25 for 4 bags of chocolate kisses and 5 packages of gummi bears. Sugar addict #2 paid $21 for 3 bags of chocolate kisses and 2 packages of gummi bears.

a] how much did each bag of Hershey kisses cost?

b] how much did each bag of gummi bears cost?

Answer 1

Let's assume, X is price of one bag of kisses, and Y is the price of one bag of bears.

4X+5y=40.25

3X+2y=21

from the second equation: y= 21-3x / 2

then plug this y in the first equation:

4x + 5(21-3x) /2 = 40.25

8x+105 -15x=80,5

x=$ 3.5 this is one bag kisses

y=( 21 -10.5) / 2= $5,25 cost one bag of bears

Answer 2

Let's use K as the cost of a bag of kisses and G as the cost of a bag of gummi bears.

It looks like we have two separate equations:

4K + 5G = $40.25 (for Sugar Addict #1)

3K + 2G = $21.00 (for Sugar Addict #2)

We need to cancel out one of those variables.

I'm going to cancel out the G by turning the 5G into a 10G and the 2G into -10G

Let's multiply both sides of the first equation by 2 and multiply both sides of the second equation by -5

2(4K + 5G)= 2(40.25)

-5(3K + 2G) = -5(21.00)

So now we have

8K + 10G = 80.50

-15K - 10G = -105.00

If we add the two equations together we have

8K + 10G = 80.50

-15K - 10G = -105.00

-7K = -24.50 Then divide both sides by -7

K = $3.50

We can now plug this into one of our original equations. I'm using the second equation

3(3.50) + 2G = 21.00

10.50 + 2G = 21.00 Now subtract 10.50 from both sides

2G = 10.50 Finally, divide both sides by 2

G = $5.25

So the cost of a bag of chocolate kisses is $3.50 and a bag of gummi bears is $5.25

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