
Justin M. answered 08/23/20
Private Math tutor
Hello, there are a couple of ways to set this up. I don't know what level your at and I cant make any assumptions about what you know. This may be lengthy and more than what your asking but I just want to make sure you understand so that it's easier for you to do on your own in the future so just bear with me.
Let letter R represent the # of red balls and
Let letter G represent the # of green balls
R= Red, G =Green
The word problem is telling you there are 22 more red balls than there are green. So(for example) if there were 1 green ball, then there would be( 1+ 22) or 23 red balls. So we translate it with this equation:
Red = Green + 22(rewrite as R=G+22)
and we know the following information
Red + Green = 50 (rewrite as R+G=50)
So to solve this we basically have to combine the two equations using a substitution method
Equation 1: R + G = 50
Equation 2: R= G +22
By plugging the second equation into the first, we can find the number of green marbles first
Replace the R in the first equation with (G+22)
R + G = 50
(G+22) + G = 50
2G + 22 = 50
- 22 -22( subtract 22 from both sides)
2G = 28(divide both sides by 2)
G=14
So now that we found that there are 14 green, just plug it into either equation to find out how many red there
are. It's easier to just use equation 2
Equation 2: R = G+22
R = 14+22
R= 36
Now you were only asked to solve for red and this was lengthy but there may be times when your asked for the number of Green also or both so now you know how to solve for both if you need to.