A ball is shot straight up into the air with an initial speed of 800ft. per sec. The height h the ball will be after t secs. is given by h=32t-16t^2. When will ball reach a height of 10,000 feet?

Question

Please explain each step in detail. Thank you!

Answer 1

The equation in the question cannot be correct. If the initial speed is 800 ft/s and it is shot up from an initial height of zero, then the equation for height vs. time (height in ft, time in sec) is

h(t) = -16t² + 800t

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