
Mark M. answered 07/28/20
Mathematics Teacher - NCLB Highly Qualified
A = 200(0.5)1000/1590
A = 200(0.5)0.628930817
A ≈ 200(0.646 655474)
A ≈ 129.331095
Stephanie T.
asked 07/28/20The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
___ mg
Mark M. answered 07/28/20
Mathematics Teacher - NCLB Highly Qualified
A = 200(0.5)1000/1590
A = 200(0.5)0.628930817
A ≈ 200(0.646 655474)
A ≈ 129.331095
Let A(t) = amount remaining after t years
A(t) = 200e-kt, for some constant, k.
Since A(1590) = 100, we have 100 = 200e-1590k.
So, e-1590k = 0.5
-1590k = ln(0.5) So, k = 0.0004359
A(t) = 200e-0.0004359t
A(1000) = 200e-0.4359 ≈ 129.3 mg
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