
Tony M. answered 08/01/20
Dr. Tony - Chemistry and assorted other subjects
The key to solving this problem requires the use of the Nernst equation:
E = Eo - (0.0592/n) log([Oxid]/[Red])
Since both electrodes are the same, Eo would be zero.
Since this is a 2-electron process, n = 2
The [Oxid} would be .100 M.
Convert the voltage from mV to V and substitute the values. Then solve for the log and complete the calculation.
log (.100/x) = 19.0 mV/(0.0592/2)